$-24-\left(-50\right)-38$
$\left(4x-y^2\right)^3$
$\frac{x^4}{x^4}$
$\frac{d}{dx}xy-3x+4x^2=7$
$36x^2+216x+349$
$y'\:=\:\:\frac{y}{x}-1$
$\frac{\left(1-p\right)^2}{p}=4$
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