$x^3-13x-12$
$xy^2\frac{dy}{dx}=y^3-x^3-x^2y$
$\lim_{x\to1}\left(x^{\frac{8}{1-x}}\right)$
$\frac{dy}{dx}+2xy=xy^4$
$\frac{x^3+2x^2+7x-2}{-x^2}$
$y''+6y'+9y=0$
$\text{sen}^2\alpha=\frac{1-\cos\left(2\alpha\right)}{2}$
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