$\left(3x+8y\right)\left(2x+4y\right)$
$1-\frac{\cos^2\left(x\right)-1}{1-\cos\left(x\right)}$
$x^{\left(2\right)}-9x+8<0$
$x^8+y^7=2$
$8+8d+4+4$
$y'+2y=8$
$\left(3a^5b^3-6ab^2\right)^2$
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