$e^5=x$
$\left(\frac{2}{x}-\frac{x}{4}\right)^2$
$4x=32$
$2\left|2-4\right|^{-2}$
$\left(y^2-\frac{4}{5}\right)^2$
$\lim\:_{x\to\:+\infty\:\:}\left(\frac{2x+a}{2x+a}\right)^{x+3}$
$2x^2-5x+x^5$
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