$\left(3xy-5y\right)^2$
$4^{8}$
$-5\left(-1\right)^4$
$x^2-16x+29=0$
$\lim_{x\to0}\left(\frac{3arc\tan\left(2x-6x\right)}{4x^2}\right)$
$\frac{\sin^3\left(x\right)}{\tan\left(x\right)-\sin\left(x\right)}$
$\frac{dy}{dx}\left(x^3+y^3=2xy\right)$
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