$\frac{x}{15}=1$
$5x;\:x=7$
$\left(mn+10\right)\left(mn-2\right)$
$\frac{2x^3-5x^2-1}{x^2-4x+5}$
$\frac{\tan\left(x\right)\cdot\sin\left(x\right)}{\tan\left(x\right)+\sin\left(x\right)}$
$r^2+7r+8$
$\left(\sin b\right)\left(\sin b\right)\left(\cot b\right)=1$
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