$49.7865671\pi24.5-.041003512\pi24.5^2$
$\int\frac{1}{t^2+3t-4}dt$
$11\left(18m^6-\frac{81}{11}m^{12}+11\right)$
$f\left(x\right)=\left(6x^3+2\right)\left(x^2-\sqrt{x}\right)$
$\left(-3\right)\left(4x+5\right)$
$8x^2-2x+21$
$\left(\frac{24x^4y^5}{3xy2}\right)$
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