$\int\left(tan\:x-1\right)dx$
$\int_0^2\left(6x^2y\right)dy$
$x+y=-2$
$\left(\frac{x}{\sqrt{2}y}\right)^2$
$\sqrt{\left(x+1\right)\sqrt{\left(x+1\right)\sqrt{\left(x+1\right)}}}$
$\frac{5a+1}{5a}-\frac{1}{a}=1$
$\frac{x-9}{x^2+4x}$
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