$\lim_{x\to0}\left(\frac{1+\cos\left(x\pi\right)}{x^2-1}\right)$
$\frac{\left(5m\right)^2-6^2}{m-6}$
$\int\frac{1}{x\sqrt{4x^2-1}}dx$
$1=\frac{2}{\:x^2}-\frac{1}{x}$
$\int\sqrt{\left(x+25\right)}dx$
$\left(-130\right)\cdot\left(-65\right)$
$\frac{1}{4x-x^2}$
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