$\lim_{x\to3}\left(\frac{27a^3+8b}{3a+2b}\right)$
$\lim_{x\to0}\left(\frac{x^2}{cosx-1}\right)$
$x\:0\:\cos\left(x\right)$
$\int_1^{\infty}\left(e^{-st}\left(6t\right)\right)dx$
$\frac{\left(12x^5y^3\right)}{\left(6xy^2\right)}$
$64x^3-343$
$4x+6\ge2x-3$
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