$\frac{d}{dx}y^2-8x=4$
$\left(2x+3\right)^2=\left(2x+3\right)\:^2$
$\left(\sqrt{x}+3+\sqrt{x}+3+\sqrt{x}+3\sqrt{x}+3\right)$
$3a\cdot1$
$\int7x^6e^{3x^7}dx$
$7^8$
$\int_{-9}^0\left(\frac{e^{\sqrt{-x}}}{\sqrt{-x}}\right)dx$
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