$\left(s+1\right)\left(s+3\right)\left(s+4\right)$
$\int\frac{\sqrt[2]{16-z^2}}{z^2}dz$
$\left(x+1\right)\left(x-9\right)$
$6x^2-16x-6$
$60-3y-9$
$\int\frac{4x^2-5}{\left(2x+1\right)\left(x^2-4\right)}dx$
$\frac{d}{dx}\left(\ln\left(x\right)+x^2\right)$
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