$\left(d^5\right)\left(d^{-6}\right)$
$-4x-6=38$
$\sqrt[4]{\frac{a^{15}}{a^3}}$
$\lim_{x\to\infty}\left(\frac{5x^2-6}{2x^2+e^x}\right)$
$\lim_{x\to+infinity}\left(\frac{x+\cos\left(x\right)}{2x+1}\right)$
$\left[\left(6x\right)\:.\:\left(1.2\right)\right]^3$
$.5^3$
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