$\lim_{x\to-3}\left(\frac{x^2-9}{\left|x^2+x-6\right|}\right)$
$-70\cdot80$
$( x + 8 ) ( x - 3 )$
$b^2-6b+5$
$4x^2+16x+16y=0$
$\int\left(\frac{-4\ln\left(\left(y\right)\right)^3}{y}\right)\:dy$
$\frac{x}{3}-\frac{1}{2}<\frac{7}{6}$
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