$1-cos\left(4x\right)=8sin^2\left(x\right)\cdot cos^2\left(x\right)$

$2\left(3x^4y\right)^3\:$

$\pi\left(4.4\right)^2$

$\frac{\left(3\left(-\frac{1}{3}\right)^3-14\left(-\frac{1}{3}\right)^2-2\left(-\frac{1}{3}\right)+1\right)}{\left(x+\frac{1}{3}\right)}$

$b^2-2b^26+b^2$

$\left(-9\right)\cdot\left(+4\right)\cdot\left(-7\right)$

$\lim_{x\to-2}\left(\frac{x^2+3x+2}{x+2}\right)$