$x^2\frac{1}{25}-4x\left(\frac{1}{25}\right)-1$
$\lim_{x\to0}\left(\frac{\left(1+x\right)^{\frac{1}{x}}}{e}\right)^{\frac{1}{2}}$
$-35-27-\left(-14\right)$
$\left(-4m+4n\right)\left(4m+4n\right)$
$\int t\cos\left(3t\right)dt$
$3x^2-27<0$
$\sqrt{1764}$
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