$b^2-2b+3=0$
$-1500-1250$
$\:-3ab+5b\:$
$\frac{ds}{dt}=4\left(1+s^2\right)tan\left(t\right)$
$\left(2+m^2-4m\right)+\left(m-2\right)$
$3j^{-3}x-6j^{4\:}$
$\frac{-36}{4}$
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