$\lim_{x\to-1}\left(\frac{2x^4+8x^3+6x+12}{x+1}\right)$
$3x\left(x-2\right)+2x=3x+8$
$\left(3a^{1+x}+4b^{1+x}\right)\left(3a^{x+1}-4b^{1+x}\right)$
$a^{12}-b^{12}$
$5u^2-5u-100$
$7^2-\left(6+2\right)$
$( 3 - 3 i ) ^ { 3 }$
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