$\log_{10}\left(x^2+6\right)-\log_{10}\left(x^2-1\right)=1$

$2\cdot\sin\left(\pi\right)+0\cdot\cos\left(\pi\right)-2$

$-4x+12<6x+2$

$\left(1-\cos\left(x\right)\right)\left(1+\sec\left(x\right)\right)\left(\cos\left(x\right)\right)=\sin^2\left(x\right)$

$0^{20}$

$15\cdot3+5$

$\int\frac{2x+3}{x^2+3x+1}dx$