$\left(2a\right)+\left(1\right)^2$
$\lim_{x\to6}\left(\frac{x^2-4x-21}{x-7}\right)$
$\frac{x^4-8x^3+3x+10}{x-5}$
$\left(\frac{x}{y^3}+5\right)\left(\frac{x}{y^3}-5\right)$
$-9x^2-6x-5$
$u^2+16u$
$\frac{x^2}{2x+1}>-1$
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