$-3b+\left(-3a\right)+4a$
$\frac{1}{2}\left(4x^2-8x+6\right)$
$10^2+100x+250$
$\left(8x+1\right)\left(4x\right)$
$-40-\left(-16\right)$
$m^2+m+16$
$\frac{8c}{ab^2-\sqrt{c}}$
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