$\frac{d}{dz}y=6^{z^5}$
$3\left(-6\right)^2+1$
$\frac{6}{7}+y\ge6$
$-x^{12}+49$
$4\left(b+1\right)+9=2\left(3b-4\right)+b$
$x^2+2x-18=0$
$\frac{dy}{y^2}=xdx$
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