$6x^50x^4+0x^3+0x^2+x-1$
$\frac{dy}{dx}=\frac{x^2-3}{y^2},\:y\left(0\right)=4$
$18-x>5$
$-3\left(2x^{-2}+3\right)$
$\int3x\left(2x^4-3\right)dx$
$x\left(x+1\right)\left(x^2+12x-84\right)$
$\int\frac{\left(x+8\right)}{\left(x\left(x+6\right)\right)}dx$
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