$\int8^{3x+4}dx$
$\left(3x+5\right)\left(x^2-2x^3\right)$
$3x^2-2x-7$
$\frac{x^3-7x+6}{x-2}$
$\left(2x^{3}-10x^{2}+9x-10\right):\left(x-4\right)$
$-2x^2+x+1$
$0\cdot3,94$
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