$\left(0.2x^3+0.1y\right)^2$
$8x^5-4x^5$
$\lim_{x\to\infty}\left(\frac{x^2+1}{x\ln\left(x\right)}\right)$
$\left(-9x^3+4x+4\right)-\left(5x^2+2x+4\right)$
$\frac{d^2}{dx}\left(\sqrt{xy}+\sqrt{y}=1\right)$
$x\left(11-3x\right)<10+10x$
$x+\frac{4}{x}=-3$
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