$20+\left(-60\right)-40-20+\left(-10\right)$
$x^2+y^2-3xy-y^2+3x^2-4xy$
$2.785-3.4+1.22$
$\frac{x^2+3x+2}{x-1}$
$\frac{1}{x-4}+\frac{1}{x+4}=\frac{16}{x^2-16}$
$\frac{dyb}{dx}=\left(x-a\right)^2$
$\frac{3x+4}{3}<\frac{6x-4}{4}$
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