$5\sec^2x-5=0$

$38-\left(-23\right)$

$y=\left(1+\sqrt{1-x}\right)^2$

$\left(4x+1\right)\cdot\left(2x^3+3x^2+5x\right)$

$\left(x+1\right)^2\left(x-2\right)+\left(x+2\right)\left(x-1\right)\left(x+1\right)$

$\int x\left(6x-3\right)^4dx$

$\frac{dy}{dx}=\frac{x^2+y^2}{x^2}$