$-7+-21-8+-64n$
$\left(\frac{1}{b}\right)^{5\:}.\left(\frac{1}{b}\right)^2.\left(\frac{1}{b}\right)^{-3}$
$49x+14x+4$
$4x+8\:+27$
$-115+13$
$4x\left(10x\right)$
$4+3\left(x-8\right)-2x=10$
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