$x^3+6x^2+12x+8$
$\frac{x^2+x-6}{x^2-6x+8}$
$5\cdot\log2\left(6x-4\right)+1=26$
$2x-3a\left(x-4a\right)$
$\left(\frac{1}{2}x-3\right)$
$\sqrt{16x^7y^4}$
$\lim_{x\to infinity}\left(\frac{\left(t+2\right)^{\frac{3}{8}}}{t^{\frac{3}{4}}}\right)$
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