$3x^2-3x\:+9$
$8\:\sec\left(x\right)\sin\left(x\right)=8\cot\left(x\right)\tan^2\left(x\right)$
$\frac{3}{2}x^2-x$
$\frac{2x^2+x}{x+1}$
$2\tan x+5=-4$
$m^2-34m+64$
$\frac{3-19x}{2x-12}\le\:2$
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