$7x+4\left(2x-6\right)$
$a^2-6a^2+12a-8$
$\left(+16\right)+\left(-7\right)-\left(-5\right)$
$-2\left(4x^2-3x+5\right)-11$
$\int-\frac{5x}{\sqrt{x^2-12}}\:dx$
$\frac{d}{dx}x^5+4xy^3-3y^5=2$
$\left(2x+1\right)^2>0$
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