$y'=4x^2y$
$x^2-\sqrt{5}x+1=0$
$\csc\left(2\right)+\cot\left(2\right)$
$\frac{\left(2x^4+4x\right)}{x-2}$
$\int\left(x^2\left(16-x^3\right)^{-2}\right)dx$
$a=6\left(a-7v\right)-6\left(y-x\right)$
$\frac{dy}{dx}=\frac{-\left(xy-y\right)}{x^2}$
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