$t^2\cdot\frac{dx}{dt}+5tx=t^4\cdot ln\left(t\right)+5$
$\left(x^2-b^2\right)^3$
$7\left(1+n\right)-9\left(8n-1\right)$
$-5y^5-3y^5-2y^5+4y^5$
$\sqrt[30]{16.x^8}$
$b^2-30b=8$
$112\cdot6$
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