$x^2-9x+42$
$x:90.000<\:700.000$
$4r^2+112r-92=0$
$\log\left(x^{2}y^{4}\right)$
$\tan^2\left(a\right)\left(1+\cot^2\left(a\right)\right)=\frac{1}{\cos^2\left(a\right)}$
$\sqrt[3]{16u^5}\cdot\sqrt[3]{4u^2}$
$\left(4\cdot\left(-1\right)-\left(3-7\right)\right)$
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