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$3cos\:x\:=\:-2$
$6^1+5$
$\frac{\sec x}{1}+\frac{\csc x}{\cot x}=\sec x$
$\int_{-4}^0\frac{2x}{x+2}dx$
$\csc\left(x\right)=\frac{1}{\tan\left(x\right)\cos\left(x\right)}$
$\left(\left(3x-5\right)\left(5x+2\right)\right)^2$
$\int_2^4\left(x^2\left(2+3x^3\right)^3\right)dx$
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