$\left(4x-6\right)\left(4x-2\right)$
$\sin^2\left(x\right)=\sin^2\left(x\right)-\cos^2\left(x\right)$
$\frac{3}{x+1}=\frac{3}{x-1}$
$0.481+0.619$
$\int_1^{\infty}\left(\frac{\left(x+2\right)}{x\left(1+x^2\right)}\right)dx$
$\frac{x^3+6x^3-12x-9}{x+3}$
$-1x^2+8x-12$
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