$b\sqrt[3]{2^2}a$
$\sqrt[6]{\frac{x+8}{x-3}}$
$x^5+3x^2=0$
$\left(\left(x^2-5x+8\right)\left(3x^2-2\right)\right)$
$8=\frac{z}{10}$
$\frac{9x^2}{-3x^2}$
$\lim_{x\to\infty}\left(\frac{x^3}{e^{.01x}}\right)$
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