$\frac{x}{4}+\frac{2}{3}<\frac{2x}{3}-\frac{1}{6}$
$\left(x^5-7\right)^4$
$\left(8x-6y\right)\left(8x-3y\right)$
$\left(3y^3\right)\cdot\left(2x^4y\right)$
$-2sin2xcos^2x+sin2x+sin2xcos2x$
$6x^2=5x\:-1$
$\left(-7\right)+2+2$
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