$\frac{x+y}{y+x}$
$\left(x+y\right)\left(x+y\right)^2$
$x^2+124x+49$
$u^2-8u-25=0$
$\left(a+2b+3c\right)-\left(4a+6b-5c\right)$
$-\frac{1}{3}\left(x-8\right)^3$
$\frac{2x^3-5x^2+x-2}{x-1}$
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