$10x^2+4x+6$
$9u+8u$
$-12<8+b$
$\lim_{x\to0}\left(\frac{sin^2x}{tan^{-1}x}\right)$
$\left(e^t-1\right)^2$
$\left(x-27\right)^3$
$3\cdot2^2+7$
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