$\left(\frac{du}{dx}\right)x+u=-1+u+u^2$
$\left(10xy-5x^3\right)^3$
$7-4\left(1\right)-5\left(7-3\right)-2+3\left(5-4\right)+8$
$\frac{5x}{2y-1}=2$
$\left(6\cdot1^2\cdot1^2+6\cdot1\right)\cdot0.87$
$\int_0^{\infty}e^{-6x}+4dx$
$\left(x^{10}-2y^5\right)^2$
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