$81a^4y+3ay^4$
$\left(4x-1\right)^2-\left(3x+1\right)^2$
$\frac{1+\tan^2\left(b\right)}{\tan2\left(b\right)}$
$\left(\frac{1}{x^2}-2x^3\right)^2$
$x^2+8x+18=0$
$9\cdot22$
$9\:xyz^4\:and\:18\:y^3\:z^2$
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