$\int\sqrt{-5-8s}ds$
$3x^2-8x=-4$
$48+\left(4+4\right)$
$102^2-3^2$
$x^3-3x\cdot2x^2+3x+5$
$-4+9x^2+6x+4x^2-8$
$\frac{\left(2\sqrt{x}+\sqrt[3]{x}\right)}{\sqrt{x}}$
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