$2x^3-9x^2-8x+15$
$\left(5+x^2\right)y''+xy'+2y$
$-5\left(\left(-8\right)\right)$
$y'=k\left(y-20\right)$
$\:x\:\:csc^2\frac{x}{x}$
$\lim_{x\to\infty}\left(\sqrt[4]{16x^4-x^3}-2x\right)$
$\frac{\tan\left(-x\right)}{\sec\left(x\right)}$
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