$\frac{x^3-7x-6}{x^2+x-20}$
$\left(x^2+y\right)^2=1$
$\left(4z-7r\right)\left(4-7r\right)\left(4z-7r\right)$
$6x^2-3y^2=1$
$\left(\frac{2}{a}-3\right)^2-9+\frac{4}{a^2}$
$\int thaxdx$
$\int x^2\left(2x^3-7\right)^5dx$
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