$\frac{3x^2}{\left(x^3+1\right)^2}$
$\int\frac{10}{x^4-8x^2-9}dx$
$\lim_{x\to\infty}\left(\frac{2x+1}{x^2+x-4}\right)$
$x\left(\frac{dy}{dx}\right)-y-3x^2=0$
$\sqrt{\left(3x-2\right)}=5$
$y^2-40y$
$x^2-2x-8$
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