$\lim_{x\to\infty}\left(\frac{tanh\left(x\right)}{tan\left(x\right)}\right)$
$-13+\frac{-5-7-9}{-7}+\frac{-12}{4}$
$-2y^5\left(4a+5a^5\right)$
$\frac{1}{\left(3-x\right)},a=1$
$\frac{6x^2+4x+3}{2x}$
$si\:x=6$
$\left(5-\sqrt{x}\right)^2$
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