$3\left(x+\frac{3}{2}\right)<\frac{1}{2}\left(x-3\right)-2x$
$-5\left(4y-u-2\right)$
$9y''-12y'+4y=0$
$\lim_{x\to\frac{\pi}{2}}\left(\left(7cos\left(x\right)\right)^{tan\left(x\right)}\right)$
$\left(7x^5-2\right)\left(7x^5+10\right)$
$\frac{x}{2x+4}$
$\frac{36}{3x^2}$
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