$16x^2+8h-3=0$
$\frac{8}{d\frac{4}{7}}$
$\left(\frac{x}{2}-y\right)^2$
$130.01cm\:+\:4.2\:+\:0.58cm\:+12.9cm$
$cos\left(x\right)+\frac{sin^2\left(x\right)}{1+cos\left(x\right)}$
$+5\:x\:\frac{4}{5}$
$\frac{2x^{3}-15x+63}{x+4}$
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