$mn.nm.m+n$
$\sin\left(\frac{3\pi}{2}-m\right)=-\cos\left(m\right)$
$\left(\sqrt{2x}\cdot\frac{1}{\sqrt[3]{3x^2}}\right)$
$5x^3-2x^2-5-2x^3=2x^3+2x^2+3x+5$
$-11+63$
$\lim_{x\to0}\frac{6x^3}{sinx-x}$
$x^2y^2-4$
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